Inequalities and functions solving by elimination and substitution
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I'm studying and I need to check these answers against mine. Thank you for your help. Inequalities and functions...
1. 5 x + 4y=8
2. 75 + 6
9
3. Distribute: 8(w-3) = -24
4. Find the value of x: 8x - (5x+6)=3
5. Solve by elimination method: what is the solution?
5x + 6y = 2
10x + 12y = 4
6. Solve by substitution method:
5x + 7y = 27
x = 51 - 9y
7. Solve:
3[75-(-48 - 56)] (my answers were 387 and 537)
8. Solve:
-18 ≤ 3x-5 ≤ -4
9. Solve:
5/8x + 1/16x = 9/16x + x
10. Is the pair parallel, perpendicular or neither?
5x + 2y =3
2x - 5y = 8
11. Solve using the elimination method.
5r - 7s = -17
7r + 5s = 65
12. System of equations ordered pair
x + 5y = 5
x=6 - 5y
13. -5 = -9
6x 10
14. On three consecutive passes, a football team gains 5 yards, loses 31 yards, and gains 50 yards. What is the total net yardage?
15. Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 mph and Train B at 80 mph. Train A passes a station at 8:25AM. If Train B passes the same station at 8:40AM, at what time will train B catch up to train A?
16. Find the slope
F(x) = -5x - 7
y-intercept (0, )
17. 8x - (5x + 6)=3
18. Find the slope x = -5
19. Domain of the function p(x) = x²-2x+2
20. 4 < 3x - 3 or 6 ≤ -2x +3
21. The product of 41% and some number d
22. 0.7x + 6 ≤ 1.1x - 9
23. e = 9f, for f
24.
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HI,
Please find the solutions/explanations attached herewith.
1. 5x + 4y=8
I think you have to graph it
Points on graphs are (0, 2), (8/5, 0)
2. 75 + 6
9
= 81/9 = 9
3. Distribute: 8(w-3) = -24
8w - 24 = -24
8w = -24 + 24
8w = 0
w = 0
4. Find the value of x: 8x - (5x+6)=3
8x - 5x - 6 = 3
3x - 6 = 3
3x = 3 + 6
3x = 9
x = 9/3 = 3
x=3
5. Solve by elimination method: what is the solution?
5x + 6y = 2-----(i)
10x + 12y = 4----(ii)
Multiply equation (i) by 2 and subtract from (ii), we will get
0 = 0
There will be INFINITELY MANY SOLUTIONS.
6. Solve by substitution method:
5x + 7y = 27
x = 51 - 9y
Substitute value of x in first equation, we will ...
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- MPhil, Institute of Advanced Studies
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