Please help solve these problems:
1. If the sides of a square are lengthened bt 5cm, the area becomes 169cm2. Find the length of a side of the original square.
2.4b2 + 49 - 28b =
3.28b2 + 196 bt + 343t2 (factor completely)
4. Solve 25x4 - 25x2 + 6 = 0
5. Solve x2 + 6x - 4 = 0
Please see the attached file for the complete solution.
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1. If the sides of a square are lengthened by 5cm, the area becomes 169cm2. Find the length of a side of the original square.
First figure out the area as a function of the length of the sides:
Let x (unit: cm) be the sides of the original ...
Poynomials are factored. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.