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Factoring Equations

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A^2- 6a +9=0

Use the even -root property to solve each question

x^2= 9/4

(x-3)^2=16

(w-3/2)^2=7/4

(w+2/3)^2=5/9

Find the perfect square trinomial whose first two terms are given.
w^2-5w

p^2+6/5p

factor each perfect square trinomial.
y^2-5y+25/4

t^2+3/5t+9/100

solve by complteing the square
3x^2-6x=24

q^2 +5q=14

x^2+4x=6

solve each equation by appropriate method
1/x^2+3/x+1=0

Find all real or imaginary solutions to each equation.

4x^2+25=0

5t^2+4t-3=0

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Equations are factored. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.

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solve by factoring
________________________________________
a^2- 6a +9=0

Solution. As , we know that if
,
then
a-3=0 or a-3=0
So, a=3 is the unique root.

Use the even -root prpoerty to solve each question

x^2= 9/4

Solution. , b y the even -root property, we have
x=3/2 or x=-3/2

(x-3)^2=16
Solution. , b y the even -root property, we have
x-3=4 or x-3=-4
So,
x=7 or ...

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  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
  • "Thank you"
  • "Thank you very much for your valuable time and assistance!"
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