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The solution can ONLY be accepted in Matlab. The problem is in the attachment file.
Planetary orbit . The expression z = a + bxy + cy + dx + ey + f is known
as a quadratic form. The set of points (x, y) where z = 0 is a conic section.
It can be an ellipse, a parabola, or a hyperbola, depending on the sign of
the discriminant b - 4ac. Circles and lines are special cases. The equation
z = 0 can be normalized by dividing the quadratic form by any nonzero
coefficient. For example, if f ≠ 0, we can divide all the other coefficients by
f and obtain a quadratic form with the constant term equal to one. You can
use the Matlab meshgrid and contour functions to plot conic sections. Use
meshgrid to create arrays X and Y. Evaluate the quadratic form to produce
Z. Then use contour to plot the set of points where Z is zero.
[X,Y] = meshgrid(xmin: deltax: xmax, ymin: deltay: ymax);
Z = a*X. ^2 + b*X. *Y + c*Y. ^2 + d*X + e*Y + f;
contour(X,Y,Z, [0 0])
A planet follows an elliptical orbit. Here are 10 observations of its position
in the (x; y) plane:
x = [1.02 .95 .87 .77 .67 .56 .44 .30 .16 .01]';
y = [0.39 .32 .27 .22 .18 .15 .13 .12 .13 .15]';
(a) Determine the coefficients in the quadratic form that fits this data in
the least squares sense by setting one of the coefficients equal to one and
solving a 10-by-5 overdetermined system of linear equations for the other
five coefficients. Plot the orbit with x on the x-axis and y on the y-axis.
Superimpose the ten data points on the plot.
(b) This least squares problem is nearly rank deficient. To see what effect this
has on the solution, perturb the data slightly by adding to each coordinate
of each data point a random number uniformly distributed in the interval
[-.005, .005]. Compute the new coefficients resulting from the perturbed data.
Plot the new orbit on the same plot with the old orbit. Comment on your
comparison of the sets of coefficients and the orbits.
**Please write comprehensive and interpretive descriptions and comments for code as well.
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