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# Choosing the correct statements about an equation

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This question concerns the equation

3x^2- 4x- 5=0

Options.

A. The equation has no real-number solutions.

B. The equation has one real-number solution.

C. The equation has two solutions x= - 0.7863 and x= 2.120 correct to 4 significant figures.

D. The equation has two solutions, x= -2.120 and x= -2.547 correct to 4 significant figures.

E. The equation has two solutions, x= -5.453 and x= -2.547 correct to 4 significant figures.

F. The equation has two solutions, x= 2.547 and x=5.453 to 4 significant figures.

G. The solutions of this equation (if any) are the values of x where the graph of y=3x^2-4x-5 cuts the x-axis (if at all).

H. The solutions of this equation are the values of x where the graph of y=3x^2-4x-5 takes its minimum value.

https://brainmass.com/math/algebra/choosing-correct-statements-equation-6697

## SOLUTION This solution is FREE courtesy of BrainMass!

3x^2 - 4x - 5 = 0.....this is a quadratic equation of form ax^2 + bx + c = 0.

a = 3
b = -4
c -5

Solutions are given by x = (-b + SQRT ( b^2 - 4ac))/2a and x = (-b - SQRT ( b^2 - 4ac))/2a

So we have x= -0.7863 and 2.120

So statement C and G are correct ( G is correct because the solution is where Y = 0 and Y will be 0 where ever it cuts the x axis)

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