100 gallons per minute flow of water at 50 degrees F passes through a theoretically 100% efficient heat exchanger. The hot side or energy to the heat exchanger is a 510 degree F hot gas (essentially steam).
Assuming the 510 degree hot gas will heat the water, what is the energy in BTU's needed to accomplish and what would the hot gas flow rate at 510 degrees need to be to perform this heating?
The heat exchange in the 100% efficient unit is:
Qwater = Qgas
(mcdeltaT)water = (mcdeltaT)gas
Thus we can calculate the heat needed to transfer to the water:
Qwater = mcdeltaT
m = 100 gpm = 833 (lb/min)
c = 1 Btu/lb.F
deltaT = 212 - 50 = 162 ...
The heat energy required to turn liquid water in to steam is calculated.