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Power Factor Correction

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Three parallel impedances in rectangular form as follows:
8.66+j5 ohm , 25+j0 ohm , 3.54+j2.54.

A 240 volt 50 Hz supply

Calculate overall power factor of the three loads.

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https://brainmass.com/engineering/power-engineering/power-factor-correction-92141

Solution Preview

Convert each impedance to admittance

Z1 = 8.66+j5
Y1 = 1/Z1 = ...

Solution Summary

This solution shows step-by-step calculations to determine the overall power factor of the three loads by first converting the impedance to admittance and then finding the total admittance.

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Alternating current circuits: Power factor corrections

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