Three parallel impedances in rectangular form as follows:
8.66+j5 ohm , 25+j0 ohm , 3.54+j2.54.
A 240 volt 50 Hz supply
Calculate overall power factor of the three loads.© BrainMass Inc. brainmass.com October 16, 2018, 6:41 pm ad1c9bdddf
Convert each impedance to admittance
Z1 = 8.66+j5
Y1 = 1/Z1 = ...
This solution shows step-by-step calculations to determine the overall power factor of the three loads by first converting the impedance to admittance and then finding the total admittance.
Alternating current circuits: Power factor corrections
What size capacitor(s) is required to correct air conditioner system power factor from 0.63 to 0.99? Is it installed in series or parallel? (installed to switch with A/C cycle)
Load amps = 12 amps
Voltage = 242 VAC
main Meter power factor A/C off = .99
main Meter power factor A/C on = .63
Load is at the end of 300' sub feeder wiring run.View Full Posting Details