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Power Factor Correction

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Three parallel impedances in rectangular form as follows:
8.66+j5 ohm , 25+j0 ohm , 3.54+j2.54.

A 240 volt 50 Hz supply

Calculate overall power factor of the three loads.

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Solution Summary

This solution shows step-by-step calculations to determine the overall power factor of the three loads by first converting the impedance to admittance and then finding the total admittance.

Solution Preview

Convert each impedance to admittance

Z1 = 8.66+j5
Y1 = 1/Z1 = ...

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