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    Power Factor Correction

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    Three parallel impedances in rectangular form as follows:
    8.66+j5 ohm , 25+j0 ohm , 3.54+j2.54.

    A 240 volt 50 Hz supply

    Calculate overall power factor of the three loads.

    © BrainMass Inc. brainmass.com October 9, 2019, 6:35 pm ad1c9bdddf
    https://brainmass.com/engineering/power-engineering/power-factor-correction-92141

    Solution Preview

    Convert each impedance to admittance

    Z1 = 8.66+j5
    Y1 = 1/Z1 = ...

    Solution Summary

    This solution shows step-by-step calculations to determine the overall power factor of the three loads by first converting the impedance to admittance and then finding the total admittance.

    $2.19