Engine consumes 5kw of power and a reactive power of 2kvar at current of (3+j2) Amps. Find the applied voltage in complex form V=(a+jb). Then use P=Re(VI*) and Q=IM(VI*) to form two simultaneous equations.
Please show workings.
V = (a+jb)
I = 3+j2
I* = 3-j2
VI* = (a+jb)*(3-j2) = (3a+2b) + ...
This solution finds the applied voltage in complex form of an engine, then forms two simultaneous equations.