Show how an ideal Operational Amplifier with an open loop gain = A can be used to provide:
i) a non-inverting amplifier with gain= +6v/v.
ii) an inverting amplifier with gain= -3v/v.
iii) an integrator with gain= +3.

Explain the purpose of every component in your circuits.

The way that you define the gain is by setting the ratio of R1 to R2. Neither of these resistors will ever have much power going thru them, so these can be very tiny - often 1/4 or 1/8 watt resistors are used. To keep power consumption down, as well as noise introduced by cheap carbon resistors, we will use resistors in a range of 10,000 Ohms thru 1 Meg Ohm.
If R2 is equal to R1, then we have Unity Gain, or a 1X Amplifier - This is a 1:1 ratio. if R2 is twice the resistance of R1, we have an Amplifier with a gain of 2 - a 2:1 ratio. To build the 2X gain amplifier, lets pick resistor values that will set the 2:1 ratio - R2 = 20,000 ohms and R1 = 10,000 ohms (20000:10000 = 2:1). That really wasn't that hard to do.
A(i) Non Inverting Amplifier :

Gain = 1 + R2/R1
6 = 1+ R2 / R1
R2 /R1 = ...

Solution Summary

Solution presents Operational Amplifier as non inverting, inverting and integrator.

a) Determine the gain-frequency characteristics of a common operationalamplifier.
b) Calculate the cut off frequency of an op-amp having characteristics
Avd - Large-signal differential voltage amplification = 20
B1 - Unity gain bandwidth = 1MHz
c) Estimate the input offset voltage for the Multisim 741 model of f

1. Show that gain rolls-off at -6 dB/octave for a passive LP filter.
2. (a) Write down the expression for the frequency-dependent open-loop gain of an operationalamplifier. Sketch the magnitude of the open-loop gain of an operationalamplifier as a function of frequency. Explain what is meant by a `single-lag' response of an

A power amplifier when driven by a current source of 5mA rms and a source resistance of 8k, delivers 12.5W signal power to an 8k load resistance. Find peak to peak value of the output voltage. If the input voltage to the amplifier shows 5V rms, determine the voltage gain of the amplifier. Show how you arrived at your answer.

3.
a) Explain what is meant by 'unconditional stability' in an op-amp.
b) Figure 2 gives the open-loop response of an uncompensated op-amp. Compensation is to be applied to the amplifier to make it unconditionally stable. Estimate the frequency at which the breakpoint of the compensated response must occur.
See attachme

Use the circuit shown below to design an inverting amplifier having a gain of -8 and an input resistance of 120 k ohms. Give the values of R1 and R2.
See attached file for full problem description.

Please look at the attached image of an audio amplifier. I know capacitors are storage elements and so forth but how do you know what a capacitor is doing at certain locations? What does terminal 7 capacitor do?

The solution covers in a detailed and explanatory manner the following topics:
- Op-amp ''golden rules'' as an introduction to op-amp circuits
- Differential amplifier structure with detailed graphical representation
- Derivation of the differential amplifiergain expression followed by the example of how to calculate t

An audio amplifier has the following frequency response (transfer function):
At 20 Hz, gain = 30 dB.
At 60 Hz, gain = 37 dB.
At 120 Hz, gain = 40 dB.
At 10,000 Hz, gain = 40 dB.
At 12,000 Hz, gain = 37 dB.
At 16,000 Hz, gain = 30 dB.
The gain of the amplifier is constant from 120 Hz to 10 kHz at 40 dB.
a. Wh

The attached figure shows an amplifier circuit.
- Sketch the small-signal equivalent circuit of the amplifier and use it to estimate the voltage gain.
- Attempt to calculate the quiescent value of VOUT.
Hint : Apply the appropriate equation:
IDS=2xIDSS/Vp^2(VDS[VGS-VP]-VDS^2/2)
Or
IDS = IDSS(1-VGS