Show how an ideal Operational Amplifier with an open loop gain = A can be used to provide:
i) a non-inverting amplifier with gain= +6v/v.
ii) an inverting amplifier with gain= -3v/v.
iii) an integrator with gain= +3.

Explain the purpose of every component in your circuits.

The way that you define the gain is by setting the ratio of R1 to R2. Neither of these resistors will ever have much power going thru them, so these can be very tiny - often 1/4 or 1/8 watt resistors are used. To keep power consumption down, as well as noise introduced by cheap carbon resistors, we will use resistors in a range of 10,000 Ohms thru 1 Meg Ohm.
If R2 is equal to R1, then we have Unity Gain, or a 1X Amplifier - This is a 1:1 ratio. if R2 is twice the resistance of R1, we have an Amplifier with a gain of 2 - a 2:1 ratio. To build the 2X gain amplifier, lets pick resistor values that will set the 2:1 ratio - R2 = 20,000 ohms and R1 = 10,000 ohms (20000:10000 = 2:1). That really wasn't that hard to do.
A(i) Non Inverting Amplifier :

Gain = 1 + R2/R1
6 = 1+ R2 / R1
R2 /R1 = ...

Solution Summary

Solution presents Operational Amplifier as non inverting, inverting and integrator.

1. Show that gain rolls-off at -6 dB/octave for a passive LP filter.
2. (a) Write down the expression for the frequency-dependent open-loop gain of an operationalamplifier. Sketch the magnitude of the open-loop gain of an operationalamplifier as a function of frequency. Explain what is meant by a `single-lag' response of an

3.
a) Explain what is meant by 'unconditional stability' in an op-amp.
b) Figure 2 gives the open-loop response of an uncompensated op-amp. Compensation is to be applied to the amplifier to make it unconditionally stable. Estimate the frequency at which the breakpoint of the compensated response must occur.
See attachme

The solution covers in a detailed and explanatory manner the following topics:
- Op-amp ''golden rules'' as an introduction to op-amp circuits
- Differential amplifier structure with detailed graphical representation
- Derivation of the differential amplifiergain expression followed by the example of how to calculate t

An audio amplifier has the following frequency response (transfer function):
At 20 Hz, gain = 30 dB.
At 60 Hz, gain = 37 dB.
At 120 Hz, gain = 40 dB.
At 10,000 Hz, gain = 40 dB.
At 12,000 Hz, gain = 37 dB.
At 16,000 Hz, gain = 30 dB.
The gain of the amplifier is constant from 120 Hz to 10 kHz at 40 dB.
a. Wh

A T-attenuator is required to be inserted between an amplifier and a transmission line. The power level to the line is required to be restricted to -3 dB. The gain of the amplifier is fixed at 24 dB and its maximum input signal is at a level of -10 dB.
Sketch a block diagram of the arrangement and calculate suitable values of

FIGURE 4 shows an amplifier circuit. Write a short report on the operation and performance of the circuit. In completing the report you should:
- Explain the operation of the circuit and in particular the role of resistors R1 and R2.
- Build the circuit in PSpice and use it to determine:
(i) the quiescent value of Vout
(ii)

Find values for the resistances shown in the circuit below such that the circuit behaves as a difference amplifier with an input resistance of 30 kohms and a gain of 80.
See attached file for full problem description.

For the depletion-load amplifier, let W1=80microm, L1=4micrometers, W2=8 micrometers and L2=32 micrometers. If the body-effect parameter X=0.2, find the voltage gain neglecting the effect on ro.
a. -44.72 V/V
b. -45.6V/V
c. 44.72 V/V
d. 45.6 V/V

FIGURE 1 shows the block diagram of a superhetrodyne radio receiver. In a test a 20 uV signal was fed from the aerial into the first stage of the receiver, a radio frequency amplifier. This signal is the passed through several stages of the receiver to eventually appear at the input to the AM detector. For the AM detector to wor