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Tank Pressures and U-tube

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A.) See attachment for diagram. Amounts from left to right, top to bottom are: 500mm, 460mm, S.G.=0.8, S.G.=1.05, 300mm, 300mm and Tank X is water.

Calculate difference in pressure between centers of tank X and Y.

B.) See attachment for diagram again. Amounts are: Pa=2.7kPa, 0.05m, 20mm, S.G.(Oil)=0.6, S.G.=1.4, 30mm, 10mm.

Find the distance d for the U tube.

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Solution Preview

The fluid of SG=0.8 has column = 500 mm in left hand side limb
and in right hand side it's height = (500+460) - (300+300) = 360 mm

SG of water = 1.0

When we go up in a fluid of given SG by a height h, the pressure decreases by = (SG*1000)*9.8*h
And when we come down, the pressure ...

Solution Summary

The solution shows each step in the calculation of the difference in pressures in two water tanks as well as the distance of a U-tube working from diagrams provided from the asker.

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A U-tube mercury manometer is connected to a closed pressurized tank as illustrated in the Figure below. If the air pressure is 2 psia, determine the differential reading (height) h. The specific weight of the air is negligible. Assume fluids are at room temperature.

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