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Instrument & Control - Transmission, Conditioning & Conversion

a) Suitable values of y and x to give the response 'A' of FIGURE 3(b)
b) The value of F, required to correct the response 'B' of FIGURE 3(b)

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a. Kc = 2500 N/A
z = 75 mm = 0.075 m
A = 5 cm^2 = 5*10^(-4) m^2

x+y = 100 mm = 0.10 m
=> y = (0.10 - x)

Given equation can be re-written as:
Po.A.x = Kc.y.Iin + Fs.z

=> Po*A*x = Kc*(0.1-x)*Iin + Fs*z

From Figure A
Po = P1 = 0.2 bar = 2*10^4 Pa
Iin = I1 = 4 A

Po = P2 = 0.5 bar = 5*10^4 ...

Solution Summary

In this solution, a numerical problem regarding a current to pressure converter is solved.

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