# BJT suitability of transistor types simple circuit

Determine the most suitable transistor from TABLE B for use in the circuit of FIGURE 3. You may assume in all cases that the transistor is biased with VBE = 0.6 V. Justify your choice in detail.

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Attached

Procedure

Determine Quiescence or Q point voltages and currents at set points in the circuit.

The Q point biasing points are determined by

Considering DC conditions so ignore (remove for analysis) any capacitors in the circuit

Considering that no input is present and biasing set by the voltage divider at the input

The circuit is thus redrawn to represent this scenario

The Q point base voltage V_BQ is thus obtained as the voltage appearing across

the voltage divider formed by 22 kΩ and 2.7 kΩ resistors across the supply, thus

V_BQ=2.7kΩ/(22+2.7)kΩ×24=2.6V

Assuming a base emitter voltage V_BE=0.6V we can then determine the Q point

of the emitter voltage, V_BQ from

V_BQ=V_EQ+V_BE

V_EQ=V_BQ-V_BE=2.6V-0.6V=2V

We can now determine the Q point currents, initially the emitter current, i_EQ

that flows from Ohm's Law

i_EQ=V_EQ/R_E =2/100=20mA

We assume the BJT transistor draws very little base current (a good

simplification as it has a very high input resistance when connected in

common emitter configuration which is the case). Then we can determine the

Q point collector current, ...

#### Solution Summary

Choosing a transistor type based on biasing of circuit, power requirements and power handling, collector current are examined.