Explore BrainMass

Explore BrainMass

    Sampling rate, Systems function, Region of convergence

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    ** Please see the attached file for the complete problem description **

    1. If the -3dB cut-off point for the filter shown (in the attachment) occurs for a real frequency of 200Hz then what should be the sampling rate (samples per sec)?

    2. The difference equation for a digital filter is given by: y(n) = 2y(n-1) + y(n-2) + x(n) - x(n-1). Compute the systems function H(z).

    3. Why must the Region of Convergence (ROC) be included with an analytic expression of the z-transform?

    4. True or False and Why: The FIR filter realization has fewer coefficients than an IIR filter but the FIR filter has stability problems that the IIR filter does not.

    5. For a causal LTI system what can you say about the poles of the z transform and the boundary of the region of convergence.

    © BrainMass Inc. brainmass.com December 24, 2021, 9:38 pm ad1c9bdddf
    https://brainmass.com/engineering/electrical-engineering/sampling-rate-systems-function-region-convergence-399272

    Attachments

    Solution Preview

    ** Please see the attached document for the complete solution response **

    Problem1
    On the x-axis, the normalized frequency of pi is equivalent to the frequency fs/2, where fs is the sampling frequency. The -3dB cut-off point is at 0.2*pi which is corresponding to 200Hz. Then the normalized frequency of pi is corresponding to 200/0.2 which is 1000Hz= fs/2. ...

    Solution Summary

    This solution explains how to solve the given problems.

    $2.49

    ADVERTISEMENT