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    find the errors in the MATLAB codes

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    The program runs, then stops and gives an error of double going into the switch. I changed the code to make it output the sounds, but my whole reasoning was to make this version work with the row vectors.

    %taking input phone numbers

    Horvector=[1209 1336 1477];
    Vervector=[697, 770, 852, 941];

    x=input('Enter Phone Number: ','s');

    a=0.5;
    t=0:1/8192:0.5;
    for i=1:length(x)
    y=z(i);
    switch y

    case '1'
    z(i)=a*sin(2*pi*Horvector(1)*t) + a*sin(2*pi*Vervector(1)*t);
    case '2'
    z(i)=a*sin(2*pi*Horvector(2)*t) + a*sin(2*pi*Vervector(1)*t);
    case '3'
    z(i)=a*sin(2*pi*Horvector(3)*t) + a*sin(2*pi*Vervector(1)*t);
    case '4'
    z(i)=a*sin(2*pi*Horvector(1)*t) + a*sin(2*pi*Vervector(4)*t);
    case '5'
    z(i)=a*sin(2*pi*Horvector(2)*t) + a*sin(2*pi*Vervector(2)*t);
    case '6'
    z(i)=a*sin(2*pi*Horvector(1)*t) + a*sin(2*pi*Vervector(2)*t);
    case '7'
    z(i)=a*sin(2*pi*Horvector(1)*t) + a*sin(2*pi*Vervector(3)*t);
    case '8'
    z(i)=a*sin(2*pi*Horvector(2)*t) + a*sin(2*pi*Vervector(3)*t);
    case '9'
    z(i)=a*sin(2*pi*Horvector(3)*t) + a*sin(2*pi*Vervector(3)*t);
    case '*'
    z(i)=a*sin(2*pi*Horvector(1)*t) + a*sin(2*pi*Vervector(4)*t);
    case '0'
    z(i)=a*sin(2*pi*Horvector(2)*t) + a*sin(2*pi*Vervector(4)*t);
    case '#'
    z(i)=a*sin(2*pi*Horvector(3)*t) + a*sin(2*pi*Vervector(4)*t);

    otherwise

    disp('Enter a valid number or * or #')

    end
    end

    %to listen to the tones with a 0.25 sec pause between each tone

    for i=1:length(x)
    sound(z(i));
    pause(0.25);
    end

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    https://brainmass.com/computer-science/matlab/find-errors-matlab-codes-100740

    Solution Preview

    First of all, you have y=z(i); in you attached codes, which should be y=x(i);

    Secondly, ...

    Solution Summary

    It finds and corrects the errors in the Matlab codes. The response was rated '5/5' by the student who posted the question originally.

    $2.19