If a telephone line can carry a signal with a baud rate of 6000 and we want to transmit data at 33,600bps, how many different signal levels will be necessary? Is this how a 33,600 bps modem operates?
To transmit data at 33600 bps using a signal with a baud rate of 6000, we would need to transmit 33600/6000 = 5.6 bits/baud.
This is effectively saying that we need to transmit 5.6 data bits per signal ...
This solution briefly explains how the required number of different signal levels are computed and how 33,600 modem operates.