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Two's complement numbers: addition, conversion to decimal

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1). Assume that the two numbers shown below are in 6-bit 2's complement form. Convert each one to decimal form.

A. (110101)base2cm
B. (010101)base2cm

2).
A. Add the following 8-bit 2's complement numbers, and state your answer in 8-bit 2's complement form: 01001010 + 11110110

B. Has overflow occurred? Answer yes or no.

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Solution Summary

Solution briefly shows the conversion calculation.

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1A. (110101)base2cm = -1*2^5 + 1*2^4 + 0*2^3 + 1*2^2 + 0*2^1 + 1*2^0 = -32 + 16 + 0 + 4 + 0 ...

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