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The molarity of 100.0 ml of solution prepared by diluting 75.0 mL of 1.5 M H2CO3.

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The molarity of a solution is calculated by taking the moles of solute and dividing by the liters of solution
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<br>Number of moles of H2CO3 in 75ml of 1.5M H2CO3 solution must be found
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<br>Molarity = moles of solute/liter of solution
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<br>ie, 1.5 = moles/0.075 liter
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<br>therefore, moles of solute = 1.5 * 0.075 = 0.1125
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<br>After diluting we have this musch number of moles in 100 ml.
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<br>Thus the new molarity = 0.1125/0.1 liter = 1.125 M ---Answer

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