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    Working with molarity and molality

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    The molarity of 100.0 ml of solution prepared by diluting 75.0 mL of 1.5 M H2CO3.

    © BrainMass Inc. brainmass.com December 24, 2021, 5:00 pm ad1c9bdddf
    https://brainmass.com/chemistry/stoichiometry/working-with-molarity-and-molality-21638

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    The molarity of a solution is calculated by taking the moles of solute and dividing by the liters of solution
    <br>
    <br>
    <br>Number of moles of H2CO3 in 75ml of 1.5M H2CO3 solution must be found
    <br>
    <br>Molarity = moles of solute/liter of solution
    <br>
    <br>ie, 1.5 = moles/0.075 liter
    <br>
    <br>therefore, moles of solute = 1.5 * 0.075 = 0.1125
    <br>
    <br>After diluting we have this musch number of moles in 100 ml.
    <br>
    <br>Thus the new molarity = 0.1125/0.1 liter = 1.125 M ---Answer

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 5:00 pm ad1c9bdddf>
    https://brainmass.com/chemistry/stoichiometry/working-with-molarity-and-molality-21638

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