What is th mole fraction of naphthalene, C10H8, in a solution prepared by dissolving 32.8 g C10H8(s) in 314 g C6H6(l)?
(Use correct significant figures.)
The molecular mass of C10H8 is 128 mol/g
Then 32.8 g of C10H8 is:
n1 = 32.8 / 128 = 0.25625 mol.
It calculates the mole fraction of naphthalene in C6H6