Consider the following reaction:
How many grams of water will be produced if the reaction is conducted with 75.6g of C4H10O and 95.5 g of oxygen?
First you need to calculate the moles of reactants.
Molecular weight of C4H10O = 4*12+10+16 =74 (g/mol)
Therefore the mole of C4H10O is = 75.6/74 = 1.02 (mol)
Molecular weight of O2 = 32 (g/mol)
Therefore the ...
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