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    I need help in this question, the diagrams are attached in the pdf file:
    6. Four possible structures are shown below for the complex trans-{ML4(n^2-C2H4)2}. L is a neutral 2 electron sigma only donor. The notation 'n^2-C2H4' means that the ethylene is bonded to the metal such that both carbon atoms are interacting simultaneously with the metal atom. When M is a low-spin, d6 metal, which of the four diastereoisomers shown below is likely to be the lowest energy and why? Your answer should include an explicit description of all ligand orbital-metal orbital interactions, including the precise metal orbits that are involved

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    Solution Preview

    Structure C seems to have the lowest energy. Here is the explanation for that:

    This is a case of π-backbonding. Bonding of π-conjugated ligands (here C2H4 or ethylene) to a transition metal (here low spin d6 metal i.e. all t2g orbitals filled and all eg orbitals empty) involves a synergic process with donation of electrons from the filled π-orbital of ligand into an empty orbital of the metal ...

    Solution Summary

    Ligand orbital for diastereoisomers are given.