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Wet and dry basis sample questions

3. 10 kg of food at a moisture content of 320% dry basis is dried to 50% web basis. Calculate the amount of water removed.

4. A batch of 5 kg of food product has a moisture content of 150% dry basis. Calculate how much water must be removed from this product to reduce its moisture content to 20% wet basis.

5. A liquid product with 10% product solids is blended with sugar before being concentrated (removal of water) to obtain a final product with 15% product solids and 15% sugar solids. Determine the quantity of final product obtained from 200 kg of liquid product. How much sugar is required? Compute mass of water removed during concentration.

Solution Preview

3) 1st step : calculate the amount of water in the food
let x = kg of water in food before removal of water

3.20 = x / (10-x) ---> dry basis equation, that is the ratio of the water to the component other than water
32 - 3.2x = x
32 = 4.2x
x = 7.619 kg water in the food

2nd step : come up with an equation that balances the mass
mass of food before water removal = mass of food after water removal + mass of water removed
let P = mass of food after water removal
let W = mass of water removed
10 = P + W
P = 10 - W -----this ...

Solution Summary

Wet and dry basis sample questions are examined.

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