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    Wet and dry basis sample questions

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    3. 10 kg of food at a moisture content of 320% dry basis is dried to 50% web basis. Calculate the amount of water removed.

    4. A batch of 5 kg of food product has a moisture content of 150% dry basis. Calculate how much water must be removed from this product to reduce its moisture content to 20% wet basis.

    5. A liquid product with 10% product solids is blended with sugar before being concentrated (removal of water) to obtain a final product with 15% product solids and 15% sugar solids. Determine the quantity of final product obtained from 200 kg of liquid product. How much sugar is required? Compute mass of water removed during concentration.

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    Solution Preview

    3) 1st step : calculate the amount of water in the food
    let x = kg of water in food before removal of water

    3.20 = x / (10-x) ---> dry basis equation, that is the ratio of the water to the component other than water
    32 - 3.2x = x
    32 = 4.2x
    x = 7.619 kg water in the food

    2nd step : come up with an equation that balances the mass
    mass of food before water removal = mass of food after water removal + mass of water removed
    let P = mass of food after water removal
    let W = mass of water removed
    10 = P + W
    P = 10 - W -----this ...

    Solution Summary

    Wet and dry basis sample questions are examined.