Chemistry Physical Chemistry 512252
Calculating Rate Constant using Hard-Sphere Theory
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I have a problem I am unable to figure out, I keep using the hard-theory formula for "A" to get the rate constant, however the value I get seems way to small every time I try to do it. Can someone please help me with this problem? I posting the homework set its problem number 5, I keep getting (4.28x10^-29dm3/mol s) as "k" please let me know if one credit is sufficient

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This solution provides step-wise answer to the given numerical problem. This solution explicitly shows each and every calculation and formula used in it, so that students can grasp the critical aspects involved in it.

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Solution provided by:
Tania Dey, PhD
Education Recent Feedback
"Thankyou for the feedback.
I have a few question though;
With the first statistic about cost below...
“According to Sigma-Aldrich catalog, cost of 1L octane is AUD $ 392.00, whereas the cost of 1L ethanol is AUD $196.00. Moreover, if ethanol is obtained from sugar industry as a by-product, it may cost even less. Source of oxygen is ambient atmosphere, so it costs nothing. So ethanol is much cheaper than petrol, in fact it is half-priced: AUD $ (392-196) = $ 196.”
I didn't think it made sense because the cost of petrol per litre is normally a dollar something or even less than a dollar not a couple of hundred of dollars. For example, a statistic that I found in america was:
"U.S. ethanol production costs are about $1.20 per gallon of ethanol, or $1.82 per gallon on a gasoline-equivalent basis."
However, I was wondering whether you could find an Australian statistic.
Also, you mentioned that H20 is not a greenhouse gas. However, in the combustion equations it is actually carbon dioxide and water vapour which are produced and they are both greenhouse gases.
Finally, how do I calculate the energy efficiency of ethanol and petrol?
" "Thank you!" "Didnt really answer my questions but gave me a start at least." "Once again this is tremendous help I can't thank you enough for not only working the problem but explaining in detail how and why!!
KR" "Awesome thank you so much for the help!!!"

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