Find the activity(not the activity coefficient) of the (C3H7)4N+ (tetrapropylammonium) ion in a solution containing 0.005 M (C3H7)4N+Br- plus 0.005 M (CH3)4N+Cl-.
Activity coefficients :
Ionic strength .001 .005 .01 .05 0.1
(C3H7)4N+ : .966 .931 .912 .85 .82
CH3)4N+: .964 .928 .902 .82 .775
The ionic strength is equal to 1/2 the summation of the <multiple> (concentration of the species multiplied by its charge squared)
Ex: Ionic strength of .02 KBr
= 1/2 ([K](1^2)+[Br](1^2))
The question here is, how do i figure out the concentration of the tetrapropylammonium ion for the concentration in the equation, and how do i figure out the activity coefficient? The ionic strength will be affected by mixing it in a different solution, and also, the solution has another ion with a different activity coefficient.
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