What is the net ionic equation for the precipitation of Lead(II) Chromate from an aqueous solution of ion.
Pb lead(II) chromate + H20--->Pb chromate?
Would you explain Le Chtelier's principle in general, and in relation to the concentration of the lead ion being reduced
what is the ionic equation for the formation of deep blue Cu(NH3)4+2 from the reaction of Cu(H20)4+2 with ammonia
How do you write an equation for the reaction of H+ with Cu(H20)4+2?
How is Le Chatelier's Principle effected in
2Ag+ (aq) + C03-2 (aq)<------>Ag2C03(s)
with the addition of Hydrogen 2H+ +CO3-2--> H2CO3(aq) ?
1. What is the net ionic equation for the precipitation of lead (II) chromate from an aqueous solution of ion.
Response: Chromate is CrO4-. Lead (II) has two positive charges. Therefore, it is Pb2+. When we put the two ions together, we need two chromates for each lead ion in order for the salt to be neutral. Therefore, lead (II) chromate is Pb(CrO4)2.
Now, we can write out the equation. All that is happening is that the aqueous salt (aq) is precipitating out as a solid (s).
Pb(CrO4)2 (aq) ------> Pb(CrO4)2 (s)
Now, we write them as ions:
Pb2+ (s) + 2 CrO4- (aq) -----> Pb(CrO4)2 (s)
2. Would you explain Le Chatelier's principle in general, and in relation to the concentration of the lead ion being reduced?
Response: The lead ion isn't being reduced in the example above. For a reduction to occur, the lead ion (Pb2+) would have to gain electrons and become neutral (Pb). That ...
This solution answers several questions regarding Le Chatelier's Principle, addressing net ionic equations, reducing concentrations and formation of deep blue.
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