Calculate the ratio of HCL molecules in the first excited rotational state to those in the ground state @ 25 C. Assume an equilibrium bond distance of 1.275 angstroms.
the angstrom part of the problem throws me off, I usually start these out by solving Change in E = ( h ) ( c )(Wo), but this is a q (rot) prob, not a q (elec). how do i solve this ?© BrainMass Inc. brainmass.com July 17, 2018, 9:24 pm ad1c9bdddf
If we have No molecules in the gnd state and Nj atoms in the excited state, , the boltzmann distribution tells us that,
Nj/No = Exp[-Ej/kT]
where K = 1.38*10^-23, the Boltzmann's constant, T is the absolute temperature and Ej is given by,
Ej = BhC J(J+1)
where h = 6.63*10^-34 JS, the Planks constant
C the velocity of licht in cm/second
and B is the rotational ...
The solution provides and easy to follow explanation of the concepts and gives all mathematical steps wherever necessary.