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# Reaction between hydrogen selenide and tin

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The composition of hydrogen selenide (H2Se) can be determined by heating tin (Sn) in a measured volume of the gas. The hydrogen selenide is decomposed, producing solid tin selenide (SnSe) and hydrogen gas. If the temperature and pressure are unchanged, the gas volume when the decomposition is over is the same as it was to begin with.

Write a balanced chemical equation for the reaction between hydrogen selenide and tin (including physical states).

Explain briefly why your equation accounts for the fact that the gas volume is unchanged.

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The composition of hydrogen selenide (H2Se) can be determined by heating tin (Sn) in a measured volume of the gas. The hydrogen selenide is decomposed, producing solid tin selenide (SnSe) and hydrogen gas. If the temperature and pressure are unchanged, the gas volume when the decomposition is over is the same as it was to begin with.

Write a balanced chemical equation for the reaction between hydrogen selenide and tin (including physical states).

Explain briefly why your equation accounts for the fact that the gas volume is unchanged.

The chemical reaction which takes place is given by the following balanced equation,

H2Se (g) + Sn (s)→ SnSe (s) + H2 (g)

We know that the ideal gas law is given by,

PV = nRT where R is the Universal gas constant.

Here, temperature T and pressure P are unchanged during the reaction.

That is V/n = RT/P = a constant

So we can write, V1/n1 = V2/n2 = a constant

But we can clearly see from the balanced reaction that number of moles of gas in the reactant and product side is the same.

That is one mole of H2Se gives one mole of H2.

Thus n1 = n2

It implies V1 = V2

That is, the gas volume when the decomposition is over is the same as it was to begin with.

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