The law of Charles & Gay-Lussac
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We wish to double the volume of a gas held at constant pressure. To what temperature must we heat it if its original temperature was (a) 0^oC, (b) 100^oC, and (c) 1000^oC?
I believe the answer is a) 546 K, b) 746 K and c) 2546 K. I need to see each step and formula to solve this question.
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Solution Summary
Precise solution is provided showing each step involved. The temperature which must be used to heat the gas at a constant pressure is determined.
Solution Preview
PV = nRT
Assuming that 'n' is constant,
PV/T is a constant.
For a constant pressure process, V/T is a constant
Let the initial temperature and volume ...
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