# Finding Energy Difference

In the CO2 laser, the pumping action involves exciting N2 molecules to the v=1 state. If ~ve=2358.57cm^-1 and ~vexe=14.324cm^-1, what is the energy difference between this transition and the transition in the CO2 from the ground to 1 quanta of energy in the asymmetric stretch.

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#### Solution Preview

dE = (2358.57 - 14.324)*100 * h*c

h = Plank's constant = 6.63*10^(-34) J-s

c = speed of light = 3*10^8 m/s

h*c = 6.63*10^(-34) * 3*10^8 ...

#### Solution Summary

The energy difference is found. The asymmetric stretch of energy is examined. Solution provides equations, calculations and answer.

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