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the heat capacity of a sample of radiator coolant

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Calculate the heat capacity of a sample of radiator coolant if a temperature rise from -5 degrees C to 142 degrees C requires 932J of heat?

A. 0.158 J/C
B. 1.37 x 10 to the power of 5 J/C
C. 6.80 J/C
D. 6.56 J/C
E. 6.34 J/C

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It shows how to calculate the heat capacity of a sample of radiator coolant given the heat required to raise its temperature. The solution is detailed and received a '5/5' rating from the student who posted the question originally.

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