What is Delta E for the formation of 8 mole of CO at 1 atm and 25°C?
C(graphite) + 1/2 O2(g)--> CO(g) ΔH = -110.5 kJ/mol
I am confused I tried -1552 and -112... I think i am close but seem to be off somewhere.
The given reaction is
8C(graphite) + 4O2 ---> 8 CO(g)
For this reaction ...
Solution includes stepwise explanation to calculate delta E formation for the given reaction.