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    Titrations - rain water with NaOH

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    60. A 155 mL sample of rainwater is titrated using 0.0095 M NaOH solution. If 4.8 mL of the NaOH solution was required to reach the endpoint, what was the pH of the rainwater? The computer gave the following hint: Calculate the number of moles of NaOH to reach the endpoint. From this calculate the hydrogen ion concentration and the pH.

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    Molarity of the solution = 0.0095M = 0.0095 moles/liter

    Amount of solution used to reach the end point = 4.8ml = 4.8*10^-3 liter

    Thus the number of moles of NaOH used up

    = ...

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