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Second order rate law calculations

Second order rate law:

1/[N02]=0.775L/(mol*s)* 645s+1/.0030mol/L= 8.3*10^2L/mol

Please provide step-by-step mathematical operation of the above.

Solution Preview

1/[NO2] = (0.775)(645) + 1/0.0030 = 833.2 mol/L

This is correct.

1/[NO2] ...

Solution Summary

The solution provides equations to answer the following second order rate law calculations.

$2.19