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Rate Law for Mechanism

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Question For the reaction
A+2B ---> E

A. Give the rate law if the mechanism is:

2A+B ---->C (slow)
B+C -----> D+A (fast)
D--------->E (fast)

B. Give the rate law if the mechanism is:

2A+B ------>C (fast)
B+C -------> D+A (slow)
D----------->E (fast)

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Solution Summary

The rate law is given for reactions whose mechanisms are known.

Solution Preview

The rate depends on the slowest step

A. Rate = k[A]^2 [B]

B. Rate = k[B][C]
Here [C] is an intermediate, so ...

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