Please show all work and explain the answer.
Question For the reaction
A+2B ---> E
A. Give the rate law if the mechanism is:
2A+B ---->C (slow)
B+C -----> D+A (fast)
B. Give the rate law if the mechanism is:
2A+B ------>C (fast)
B+C -------> D+A (slow)
The rate depends on the slowest step
A. Rate = k[A]^2 [B]
B. Rate = k[B][C]
Here [C] is an intermediate, so ...
The rate law is given for reactions whose mechanisms are known.