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For the reaction SO3 + H2O yields H2SO4, calculate the percent yield if 500.g of sulfur trioxide react with excess water to produce 575 g of sulfuric acid? 82.7%, 88.3%, 91.2%, 93.9%

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Solution Summary

Calculation of percentage yield of sulfuric acid for given reaction are determined.

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the answer is 93.9%

SO3 + H20 -----> H2SO4
MOLAR MASS 80 18 98

NOW, THEORATICALLY,

80 g SO3 gives = 98 g ...

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