What is the pH of an aqueous solution that contains 0.15M NH3 and 0.05M (NH4)2SO4? The Kb for NH3 is 1.8 x 10-5.© BrainMass Inc. brainmass.com December 24, 2021, 6:06 pm ad1c9bdddf
* The 0.05M of (NH4)2SO4 salt will dissociate completely to produce 0.1M of NH4+
(NH4)2SO4(aq) <--> 2NH4+(aq) + SO42-(aq)
* Ammonia will ionize to produce NH4+ and OH- according to the value for Kb
NH3(aq) + H2O(l) <-->NH4+(aq) + OH-(aq)
and at equilibrium:
Kb =1.8 x 10-5 = [NH4+][OH-]/[NH3]
Set X = amount of NH3 that will ionize as the reaction goes to equilibrium
* The added salt is not directly altering the concentration of either NH3 or OH-
* Therefore if X M of NH3 ionize, then X M of OH- are produced at equilibrium
* The concentration of NH4+ at ...
pH of an aqueous solution that contains 0.15M NH3 and 0.05M (NH4)2SO4.