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    pH of an Aqueous Solution That Contains NH3 and (NH4)2SO4

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    What is the pH of an aqueous solution that contains 0.15M NH3 and 0.05M (NH4)2SO4? The Kb for NH3 is 1.8 x 10-5.

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    * The 0.05M of (NH4)2SO4 salt will dissociate completely to produce 0.1M of NH4+

    (NH4)2SO4(aq) <--> 2NH4+(aq) + SO42-(aq)

    * Ammonia will ionize to produce NH4+ and OH- according to the value for Kb

    NH3(aq) + H2O(l) <-->NH4+(aq) + OH-(aq)

    and at equilibrium:
    Kb =1.8 x 10-5 = [NH4+][OH-]/[NH3]

    Set X = amount of NH3 that will ionize as the reaction goes to equilibrium

    * The added salt is not directly altering the concentration of either NH3 or OH-
    * Therefore if X M of NH3 ionize, then X M of OH- are produced at equilibrium
    * The concentration of NH4+ at ...

    Solution Summary

    pH of an aqueous solution that contains 0.15M NH3 and 0.05M (NH4)2SO4.

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