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    Learning Curve Problems

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    1) Given the following information, determine the equation for the unit formulation. (Round intermediate calculations to 4 decimal places)

    Unit Number (X) Unit Cost(Y)
    1 $900.00
    2 780.00
    3 717.37
    4 676.00

    - Y = (900)(X) 0.6931
    - Y = (900)(X) -0.2065
    - Y = (900)(X) 0.9000
    - Y = (900)(X) -0.1521

    2) It cost a contractor $9,765 to manufacture their first unit. The company expects to experience an 82% unit learning curve. Estimate the cost of the 7th unit. (Round intermediate calculations to 4 decimal places)
    - $ 7,615
    - $ 8,593
    - $ 6,821
    - $ 5,594

    3) If a company took 100 hours to assemble their first unit and 90 hours to assemble the second unit, we might expect it to take:
    - 81 hours to assemble the fourth unit.
    - 72.25 hours to assemble the third unit.
    - 72.25 hours to assemble the fourth unit.
    - 70 hours to assemble the third unit.

    4) It took a contractor 1285 hours to manufacture their first unit of an item. If the contractor expects to achieve a 92% unit learning curve, how many hours would be required to manufacture units 52-100? (Use the tables provided in the lesson).
    - 290,475
    - 38,289
    - 37,488
    - 284,398

    5) In the following unit learning curve equation:
    Y=34(X)-0.134425

    - The slope equals 88%.
    - Y represents the cost of the 34th unit.
    - Y is the cost of the first unit.
    - The slope equals 91.1%

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    https://brainmass.com/business/managerial-statistics/564700

    Solution Preview

    1. 780/900 = 86.6667%, so we know the slope is 86.6667%. The exponent on X is given by:
    ln(0.866667)/ln(2) = -0.2065

    Y = 900 X ^(-0.2065)

    2. Given a slope of 82%, we calculate the ...

    Solution Summary

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