a. In guinea pigs, black coat color (B) is dominant over white coat color (b). When a true breeding black guinea pig is crossed to a true breeding white guinea pig, what is the probability that their progeny will be black? Explain.
b. If two heterozygous black guinea pigs are crossed, what fraction of their progeny will be black? Explain.
c. Lack of pigmentation (albinism) in humans is the result of a recessive allele (a), and normal pigmentation is the result of its dominant allele (A). Two normal parents have an albino child. Determine the probability that the next child is albino. Explain.
d. The genotypes of two individuals in a tetrahybrid cross are AABbCCDd and AabbccDD. What fraction of their offspring would be heterozygous for all four traits? (Assume independent assortment for all four traits, and show your calculations.)
e. A man of blood group B is being sued by a woman of blood group A for paternity. The woman's child is blood group O. Can this man be the father of this child? Explain.© BrainMass Inc. brainmass.com October 25, 2018, 9:06 am ad1c9bdddf
Punnett squares are the easiest way to look at genetics for ...
This solutions provides a spreadsheet of punnett squares that looks at the odds of various genetic combinations. Primarily simple, 1-gene examples with 1 tetrahybrid.
Set up and Complete Punnett Square
Bob and Sally recently married, Upon deciding to plan a family , both Sally and Bob find out that they are both heterozygous for cystic fibrosis, but neither of them has symptoms of the disorder. Set up and complete a punnett square for cystic fibrosis for this couple; when doing the Punnett Square, C=normal allele; and c=allele for cystic fibrosis. Based on punnett square, calculate chances ( percentages ) for having a healthy child ( not a carrier), a child trait is a carrier for the cystic fibrosis?View Full Posting Details