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The Punnett Square: Probability of Inheriting Cystic Fibrosis

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Bob and Sally recently married. Upon deciding to plan a family, both Sally and Bob find out that they are both heterozygous for cystic fibrosis, but neither of them has symptons of the disorder.

Set up and complete a Punnett Square for cystic fibrosis for this couple; turn in the Punnett square. When doing the Punnett Square, assume that C=normal allele and c=allele for cystic fibrosis.

Based on the Punnett square, calculate chances (percentages) for having a healthy child ( not a carrier), a child that is a carrier for the cystic fibrosis trait, and a child with cystic fibrosis. Turn in these percentages.

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Solution Summary

This solution is an explanation to the chances of inheritance of cystic fibrosis from parents to offspring based on an example. It is explained with the help of a Punnett Square. It is a single page MS Word document with original contents.

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The parents, Bobby and Sally are heterozygous for cystic fibrosis. So they are carriers of the disease. Hence the genotype for both will be Cc .

The ...

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