Bob and Sally recently married. Upon deciding to plan a family, both Sally and Bob find out that they are both heterozygous for cystic fibrosis, but neither of them has symptons of the disorder.
Set up and complete a Punnett Square for cystic fibrosis for this couple; turn in the Punnett square. When doing the Punnett Square, assume that C=normal allele and c=allele for cystic fibrosis.
Based on the Punnett square, calculate chances (percentages) for having a healthy child ( not a carrier), a child that is a carrier for the cystic fibrosis trait, and a child with cystic fibrosis. Turn in these percentages.
The parents, Bobby and Sally are heterozygous for cystic fibrosis. So they are carriers of the disease. Hence the genotype for both will be Cc .
This solution is an explanation to the chances of inheritance of cystic fibrosis from parents to offspring based on an example. It is explained with the help of a Punnett Square. It is a single page MS Word document with original contents.