Purchase Solution

Z-Test

Not what you're looking for?

Ask Custom Question

Hypothesis is it takes 25 minutes or less to serve a meal. The sample size was 20 people observed for 80 minutes. The average time it took for all people to be served was 24 minutes.

Purchase this Solution
Solution Summary

The solution discusses the hypothesis is it takes 25 minutes or less to serve a meal. The sample size was 20 people observed for 80 minutes. The average time it took for all people to be served was 24 minutes.

Solution Preview

From your posting I believe you are asking how to tackle the problem with a Z-test. First of all your sample size of 20 is too low. And there needs to be a breakdown of the people into males and females. I have described this below.

Your null hypothesis (NH) could be better written as:

NH = any difference between the time taken to serve a ...

Purchase this Solution
Free BrainMass Quizzes
Measures of Central Tendency

Tests knowledge of the three main measures of central tendency, including some simple calculation questions.

Terms and Definitions for Statistics

This quiz covers basic terms and definitions of statistics.

Measures of Central Tendency

This quiz evaluates the students understanding of the measures of central tendency seen in statistics. This quiz is specifically designed to incorporate the measures of central tendency as they relate to psychological research.

Know Your Statistical Concepts

Each question is a choice-summary multiple choice question that presents you with a statistical concept and then 4 numbered statements. You must decide which (if any) of the numbered statements is/are true as they relate to the statistical concept.

View More Free Quizzes
Related BrainMass Solutions

  • Finding test statistics and critical values for one proportion z

    Use the one-proportion z-test to perform the specified hypothesis test. Use the critical-value approach.

  • One Tail/Two Tail Rejection Regions

    For each of the following test and z values, determine the p-value for the test: a. left-tail test and z = -1.62 b. right-tail test and z = 1.43 c.

  • P-value and its' relationship to Z-test and T-test

    325213 P-value and its' relationship to Z-test and T-test What is the P-value and what is its' relationship to the Z-test and the T-test?

  • Choosing between a Z and T test

    T-test can be replaced by Z-test if the sample size n is larger than 30. If n<30, then we choose T-test or Z-test depending on whether or not we know the population standard deviation; The solution explains how to choose between a Z and a T test.

  • Choosing between a z-test and a t-test.

    184276 This question is designed to assess the similarities and differences between a Z-score and a t-test. Under what circumstances would you conduct a z-test? When would you preform a t-test?

  • Stanford-Binet IQ Test Scores: Distribution, z score, probability

    Sketch the distribution of Stanford -Binet IQ test scores. b. Write the equation that gives the z score corresponding to a Stanford-Binet IQ test score. Sketch the distribution of such z scores. c.

  • Test statistic and p-value for sample

    With these two assumptions, the Z test can be used for given data.

  • T-tests and z-tests

    317963 Difference in T-test and Z-test: number of variables, levels of measurement How many variables are in a Z and T test? What are they? What are their levels of measurement?

  • Test Hypothesis for Job Satisfaction

    0 (or Ha: m < m 0) TWO -TAILED TEST H0: m = m 0 Ha: m ¹ m 0 Test statistic: Rejection region: z > za (or z < - za) Rejection region: z < -za /2 (or z > za /2) where za is the z-value such that P(z > za) = a; and za/2 is the

  • Two-Sided Test

    (72))=1.41 Z2=(131.5-122)/(15/sqrt(72))=5.37 P(1.41<z<5.37)=P(z<5.37)-P(z<1.41)=1-0.9207=0.0793 Power of the test=1-0.0793=0.9207 (c) z1=(124.5-136)/(15/sqrt(72))=-6.51 Z2=(131.5-136)/(15/sqrt(72))=-2.55 P(-6.51<z<-2.55)=P(z<-2.55)-P(z<-6.51)=

View More Related Solutions