4.9: this is a normal distribution question:
Let's define: m=1000, S2 = 10000,
then the standard deviation is SD=SQRT(S2)=100
(a) by the formula: z = (X-m)/SD
z1 = (1200-1000)/100 = 2
from a z table, we find that Pr(z<2) = 0.9773

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