On January 7, 2000, the Gallup Organization released the results of a poll comparing lifestyles of today with those yesteryears. Then poll results were based in telephone interviews with a randomly selected national sample of 1,031 adults, 18 years and older, conducted December 20-21, 1999. One question asked if the respondent had vacationed for six days or longer within the last 12 months. Suppose that we wish to use the poll's results to justify the claim that more than 40 percent of U.S. adults have vacationed for six days or longer within the last 12 months. The poll actually found that 42 percent of the respondents had done so.
a) If, for the sake of argument, we assume that the claim were true, calculate the probability of observing a sample proportion of 42 percent or more.
b) Would you conclude that more than 40 percent of U.S. adults have vacationed for six days or longer within the last 12 months? Explain.
For part A, you can use the standard z-score calculation of :
p +/- z(1.96) times the square root of (p(1-p)/n)...based on your data, I come up with 0.4 plus and minus 0.0299, or 0.3701 and 0.4299. This means that you are 95% confident that between 37% and nearly ...
Gallup Organizations released results of poll comparing lifestyles are determined.