# Probability of Proportions

A given population proportion is .25. For the given value of n, what is the probability of getting each of the following sample proportions?

a. n = 110 and pÌ‚ â‰¤ .21

b. n = 33 and pÌ‚ > .24

c. n = 59 and .24 â‰¤ pÌ‚ < .27

d. n = 80 and pÌ‚ < .30

e. n = 800 and pÌ‚ < .30

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7.22. A given population proportion is .25. For the given value of n, what is the probability of getting each of the following sample proportions?

Answers

a. n = 110 and pÌ‚ â‰¤ .21

Here we can assume that p follows normal distribution with Âµ = 0.25 and standard deviation Ïƒ = = = 0.041286.

We need P (pÌ‚ â‰¤ .21). Standardizing p using and from standard normal tables, we have

P (pÌ‚ â‰¤ .21) = = P (Z < -0.96885) = 0.16631

Details

Normal Probabilities

Common Data

Mean 0.25

Standard Deviation 0.041286

Probability for X <=

X Value 0.21

Z Value -0.968851427

P(X<=0.21) 0.166309662

b. n = 33 and pÌ‚ > .24

Here we can assume that p follows normal distribution with Âµ = 0.25 and standard deviation Ïƒ = = = 0.075378.

We need P (pÌ‚ > .24). Standardizing p using and from standard normal tables, we have

P (pÌ‚ > .24) = = P (Z > -0.132665) = 0.5528

Details

Normal Probabilities

Common Data

Mean 0.25

Standard Deviation 0.075378

Probability for X >

X Value 0.24

Z Value -0.132664703

P(X>0.24) 0.5528

c. n = 59 and .24 â‰¤ pÌ‚ < .27

Here we can assume that p follows normal distribution with Âµ = 0.25 and standard deviation Ïƒ = = = 0.056373.

We need P (.24 â‰¤ pÌ‚ < .27). Standardizing p using and from standard normal tables, we have

P (.24 â‰¤ pÌ‚ < .27) =

= P (-0.17739 < Z < 0.35478)

= 0.2090

Details

Normal Probabilities

Common Data

Mean 0.25

Standard Deviation 0.056373

Probability for a Range

From X Value 0.24

To X Value 0.27

Z Value for 0.24 -0.177389885

Z Value for ...

#### Solution Summary

The probabilities of proportions are examined.