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Linear Regression Equation and Its Interpretations

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Simple Linear regression results:
Dependant Variable : Stoppages
Independent Variable : Temp Variability
Stoppages = 5.740207 - 0.27559829 Temp Variability
Sample Size: 16
R (correlation coefficient) - -0.04475
R-sq = 0.20022592
R-sq = 0.20022592
Estimate of Standard Deviation : 2.0759327

PARAMETER ESTIMATES:

PARAMETER ESTIMATE STD. ERR. DF T-STAT P- VALUE

Intercept 5.740207 1.9030284 14 3.016354 0.0092
Slope -0.28759829 0.14741498 14 -1.8721495 0.0822

With this information, answer the questions below and provide explanations.

a. What is the correlation coefficient ?
b. what is the mean?
c. Is this a strong or weak correlation?
d. What is the coefficient of determination?
E. What does this tell you?
f. What is the slope term?
h. What is the intercept term?
i. What is the regression equation?
j. How many stoppages does this model predict what the temperature varies 9 degrees?

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Solution Summary

Solution Describes how to find correlation coefficient, slope, determination,intercept etc for given regression parameters.

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a. What is the correlation coefficient ?
-0.4475
Please check your figure. Correlation coefficient is square root of r-square value.

b. what is the mean?
It means that there is a negative linear relationship between Stoppages and temperature variability. As ...

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