# Statistics Control charts, probabilities

This is for Quality Control

Consider the xbar chart for the piston-ring example as follows, let ring diameter be normally distributed, and the sample size is n = 5.

a) Find the two-sigma control limits for this chart.

b) Suppose it was suggested that the two-sigma limits be used instead of the typical three-sigma limits. What effect would this have on the occurrence of false alarms?

c) What effect would the use of two sigma limits have on the in-control ARL of the chart.

d) Discuss the meaning of your findings in parts (b) and (c).

https://brainmass.com/statistics/probability/statistics-control-charts-probabilities-13274

#### Solution Preview

1. Consider the xbar chart for the piston-ring example as follows, let ring diameter be normally distributed, and the sample size is n = 5.

a) Find the two-sigma control limits for this chart.

Solution: We divide UCL-average by 3 to get 1-sigma limit:

1-sigma limit = (74.0135-74)/3 = 0.0045

Average + 1-sigma limit = 74.0000 + 0.0045 = 74.0045

Average - 1-sigma limit = 74.0000 + 0.00045 = 73.9955

These lines can now be ...

#### Solution Summary

The expert examines statistics control charts for probabilities.