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    Statistics: Condition Probability

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    A survey showed that 24% of college students read newspapers on a regular basis and that 81% of college students regularly watch the news on TV. The survey also showed that 21% of college students both follow TV news regularly and read newspapers regularly.

    (a) What is the probability that a randomly selected college student reads newspapers regularly, given that he or she watches TV news regularly? Round your answer to 2 decimal places.
    (b) What is the probability that a student watches TV news regularly, given that he or she regularly reads newspapers? Round your answer to 2 decimal places.

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    https://brainmass.com/statistics/probability/statistics-condition-probability-203338

    Solution Preview

    P(NP) = 24% = 0.24, P(TV) = 81% = 0.81, P(Both NP and TV) = 21% = ...

    Solution Summary

    This solution is comprised of a complete, neat and step-by-step response which concisely presents the equation necessary to compute these types of probability based calculations.

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