Statistics
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Workers in an industry earn $17.35 per hour on the average; the standard deviation is $2.10 per hour. If a sample of 40 workers is taken, how likely is it the mean will be:
a. Between $16.80 and $17.00?
b. Above $17.22?
Please use the attachments provided and not only excel functions.
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M = 17.35, SD = 2.10; n = 40, z = (x - M)/(SD/sqrt n)
(a) z1 = (x1 - M)/(SD/sqrt n) = (16.80 - ...
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