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Problem on Probability of Normal Distribution

Average length of stay in hospital is 60 days with a standard deviation of 15.

What percentage of patients stay less that 50 days? The probability is 0.9535 that a patient will stay between
____(b_____and _______(c)_______days.

(Hint: to start find two z-scores equidistant from the center such that the area between them is 0.9534.)