15. Captain D's tuna is sold in cans that have a net weight of 8 ounces. The weights are normally distributed with a mean of 8.025 ounces and a standard deviation of 0.125 ounces. You take a sample of 36 cans. Compute the probability that the sample would have a mean:

a. greater than 8.03 ounces?
b. less than 7.995 ounces?
c. between 7.995 and 8.03 ounces?

16. The mean hourly wage of finish carpenters in Phoenix, AZ is $16.50 per hour. What is the likelihood that we could select a sample of 40 carpenters with a mean of $16.75 or more? The standard deviation of the sample is $1.75.

17. The anticipated mean weight of logging trucks entering the Hafner Saw mill in southern Ohio is 78,000 pounds. A sample of 48 trucks has a mean of 78,700 pounds and a standard deviation of 1,750 pounds. What is the probability that a sample of this size could come from the population with a mean of 78,000 pounds?

... Please see the attachments. The solution provides step by step method for the calculation of Normal probability, confidence interval and sample size. ...

Sample size & Normal Probability. ... The solution provides step by step method for the calculation of probability using the Z score and sample size. ...

... Use probability proportional to size (PPS) sampling to do the following: ...Probability Proportional to Size (PPS) sampling is a well known method in auditing. ...

... The solution provides step by step method for the calculation of testing of hypothesis, confidence interval, sample size, normal probability and regression ...

... e) For a random sample size 3, obtain the probability that the sampling error made in estimating the population mean by the sample mean will be 1 year or less ...

... Page 1 Binomial Probabilities. Data Sample size 20 Probability of an event of interest 0.85. Statistics Mean 17 Variance 2.55 Standard deviation 1.596871942. ...

... Estimate the probability that of 10,000 randomly selected hair dryers, exactly 225 are ... n = 9, x = $3262, s = $836 9) Find the minimum sample size you should ...

... Result Sample Size Needed 554 Normal. Normal Probabilities. Common Data Mean 60000 Standard Deviation 2000. Probability for X > X Value 66000 Z Value 3 P(X>66000 ...