Purchase Solution

# Independent Variables

Not what you're looking for?

Let X1 and X2 be two independent random variables having Poisson Dist. with parameters mew(subscript1)=2 and mew(subscript 2)=3 respectively. Then the marginal distribution for the random variable X2 is :

a.) h(X2) = e^-2*2^Xz/X2!, x2=0,1,2,3,...

b.) h(X2) = e^-5*5^Xz/X2!, x2=0,1,2,3,...

c.) h(X2) = e^-3*3^Xz/X2!, x2=0,1,2,3,...

d.) h(X2) = e^-3*3^Xz/X2!, x2=1,2,3,...

##### Solution Summary

Let X1 and X2 be two independent random variables having Poisson Dist. with parameters mew(subscript1)=2 and mew(subscript 2)=3 respectively. Then the marginal distribution for the random variable X2 is :

a.) h(X2) = e^-2*2^Xz/X2!, x2=0,1,2,3,...

b.) h(X2) = e^-5*5^Xz/X2!, x2=0,1,2,3,...

c.) h(X2) = e^-3*3^Xz/X2!, x2=0,1,2,3,...

d.) h(X2) = e^-3*3^Xz/X2!, x2=1,2,3,...

##### Solution Preview

Because, marginal distribution of X2
f(X2) = integration (- ...

Solution provided by:
###### Education
• MSc , Pune University, India
• PhD (IP), Pune University, India
###### Recent Feedback
• " In question 2, you incorrectly add in the \$3.00 dividend that was just paid to determine the value of the stock price using the dividend discount model. In question 4 response, it should have also been recognized that dividend discount models are not useful if any of the parameters used in the model are inaccurate. "
• "feedback: fail to recognize the operating cash flow will not begin until the end of year 3."
• "Great thanks"
• "Perfect solution..thank you"

##### Measures of Central Tendency

This quiz evaluates the students understanding of the measures of central tendency seen in statistics. This quiz is specifically designed to incorporate the measures of central tendency as they relate to psychological research.