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# Americans ate an average of 25.7 pounds of confectionary pro

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Americans ate an average of 25.7 pounds of confectionary products each last year and spent an average of \$61.50 per person doing so. If the standard deviation for consumption is 3.75 pounds and the standard deviation for the amount spent is \$5.89, find the following:

a. The probability that the sample mean confectionary consumption for a random sample of 40 American consumers was greater than 27 pounds.

b. The probability that for a random sample of 50, the sample mean for confectionary spending exceeded \$60.00.

https://brainmass.com/statistics/probability/americans-ate-an-average-of-25-7-pounds-of-confectionary-pro-415802

#### Solution Preview

Americans ate an average of 25.7 pounds of confectionary products each last year and spent an average of \$61.50 per person doing so. If the standard deviation for consumption is 3.75 pounds and the standard deviation for the amount spent is \$5.89, find the following:

a. The probability that the sample mean confectionary consumption for a random sample of 40 American consumers was greater than ...

#### Solution Summary

Americans ate an average of 25.7 pounds of confectionary products each last year and spent an average of \$61.50 per person doing so. If the standard deviation for consumption is 3.75 pounds and the standard deviation for the amount spent is \$5.89, find the following:

a. The probability that the sample mean confectionary consumption for a random sample of 40 American consumers was greater than 27 pounds.

b. The probability that for a random sample of 50, the sample mean for confectionary spending exceeded \$60.00.

\$2.19